Steps of Design
- Defining our loads.
- Sizing inverter.
- Sizing panels.
- Sizing batteries.
- Sizing a charge controller.
- Panel connection.
Step 1: Defining our Loads
Device | Number | Power/device(w) | Number of Hours | Energy (wh) |
Lamp | 1 | 18 w | 4 | 72 wh |
Fan | 1 | 60 w | 2 | 120 wh |
Refrigerator | 1 | 75 w | 12 | 900 wh |
Total | 153 w | 1092 wh/day |
Step 2: Sizing Inverter
- An inverter is used in the system where AC power output is needed.
- The input rating of the inverter should never be lower than the total wattage of appliances.
- The inverter must have the same nominal voltage as your battery.
- For stand-alone systems, the inverter must be large enough to handle the total amount of watts you will be using at one time.
- For grid-tie systems or grid-connected systems, the input rating of the inverter should be the same as the PV array rating to allow for safe and efficient operation.
- The inverter power should be greater than the load’s total wattage by 25% or 30%.
- The inverter’s continuous power = 1.3* total wattage = 1.3153 W = 198.9 W.
- If the system has motors, compressors, refrigerators, pumps, and washing machines, we need to make sure that the inverter can withstand the starting current.
- The surge power of these devices is found on the label of them.
- If you donβt know, you can assume the surge power = 3x β 4x the wattage of these devices.
- The inverter surge power = Lamp + Fan + 4 Refrigerators = 378 W.
- We need an inverter with a continuous power of 198.9 W and a surge power of 378 W.
Step 2: Sizing Inverter


Step 3: Sizing Panels
- The total energy required by the loads is 1092 Wh/day.
- The total energy needed from panels = total energy * 1.3 (a safety factor to accumulate for all the losses in the PV system in addition to the panels not operating at the optimum conditions) = 1092 Wh * 1.3 = 1419.6 Wh.
- The power of panels = πππ‘ππ ππππππ¦ ππππππ ππππ / π π’π βππ’ππ
- = 1419.6πβ2 βππ’ππ = 709.8W.
- We will select Sunpower SPR-200-BLK-U.
- Number of panels = πππ‘ππ πππ€ππ / πππ€ππ ππ πππ πππππ
- =709.8200=3.549 ππ ππππππ₯ππππ‘πππ¦ 4 ππππππ .
- The power of panels = 4 * 200 = 800 W.
Step 4: Sizing Batteries
- Assuming the lowest temperature in the location is -20Β°C. Then the nominal capacity will be 160 Ah instead of 330 Ah.
- The temperature correction coefficient = 160π΄β / 330π΄β=0.48.
- Ah of batteries = πππ‘ππ ππππππ¦ ππππππβπ·ππ¦π ππ ππ’π‘πππππ¦ / π·ππ·βππ¦π π‘ππ π£πππ‘πππβππππππππ‘π’ππ πππππππ‘πππ πππππππππππ‘
- = 1419.6πββ2 / 0.8β12πβ0.48
- = 616.15 Ah.
- Number of series batteries = ππ¦π π‘ππ π£πππ‘πππ / πππ‘π‘πππ¦ π£πππ‘πππ = 12/12 = 1 πππ‘π‘πππ¦ ππ πππβ π πππππ π π‘ππππ.
- Number of parallel strings = π΄β ππππ’ππππ / π΄β ππ πππ πππ‘π‘πππ¦=616.15 / 330=1.86 ππ ππππππ₯ππππ‘πππ¦ 2 ππππππππ π π‘πππππ .
- Total batteries = 2*1 = 2 batteries.

Step 5: Sizing Charge Controller
- The power of panels = 800 W and the system voltage is 12 V.


Important Note:
- The series panel connection is dependent on the MPPT range.
- We try to make the panel voltage at the middle value of this range.
- If the MPPT range is not available, we will take half of the open circuit voltage value.
Step 6: Panel Connection
- Assuming selection of the open circuit voltage at the middle of the maximum PV open-circuit voltage = 150/2=75 π.
- Number of panels in series = π·ππ πππ ππππ πππππ’ππ‘ π£πππ‘πππ / πππππ ππππ πππππ’ππ‘ π£πππ‘πππ
- =75 π / 47.8 π=1.57 ππ ππππππ₯ππππ‘πππ¦ 2 ππππππ ππ π πππππ .
- Panels in parallel = πππ‘ππ ππ’ππππ ππ ππππππ / ππ’ππππ ππ ππππππ ππ π πππππ =4/2=2 ππππππππ π π‘πππππ .
- The open circuit voltage at lowest temperature = number of series panels * open circuit voltage of one panel at lowest temperature.
- = 2(47.8+(0.065*(25+20))=101.45V < 150 V.
- The input current of the charge controller = short-circuit current of the PV panel * number of parallel strings * safety factor (1.25 or 1.3).
- = 1.2525.4 = 13.5 A < 50 A



Electrical electrical technician
Bms
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